Sunday, 17 May 2015

Florida, Las Vegas, best for holiday savings

NEW YORK, Santa Barbara, and San Francisco are the most expensive US vacation destinations of 2015, while Las Vegas (Nevada) and Jacksonville and Orlando in Florida are the cheapest, according to a GOBankingRates study of the most and least affordable cities for holidaymakers. 

The study look at 50 of the most popular vacation destinations in the US, ranking their affordability on factors that impact travellers' budgets the most: hotel prices, airfare, food and drink costs, and transport expenses.

‘You don't have to drive to the middle of nowhere to find a cheap summer vacation,’ said Casey Bond, GOBankingRates' editor-in-chief.

‘Some of the least expensive destinations on our list are also the most popular — with Vegas taking the No. 1 spot. Still, it's important to remember that saving money on vacation doesn't end with finding a cheap flight or inexpensive hotel room; don't blow your budget on squeezing in visits to crowded tourist traps. You can have more fun, spend less money, and get a more authentic experience at some of the cheapest cities in the country.’

Go Holiday news :

Picture Credit: Las vegas sign night philipp von ostau by Philipp von Ostau - Own work. Licensed under CC BY-SA 3.0 via Wikimedia Commons , Friendship Fountain at Night by I, Jonathan Zander. Licensed under CC BY-SA 3.0 via Wikimedia Commons 

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